<div>By The Way, Nick the Charge Q is also a function of the number</div>
<div>of upper Fermi Level (conduction electrons) available from the</div>
<div>two materials.</div>
<div>IOW, ultra thin layers of material cannot provide enough of themfor the required charge .</div>
<div>If I recall the electroless nickel coating was less than 1/2 micron thick which formed</div>
<div>sort of a "double dipole" with the zirconium, that aligned the disc in the 75,000 volt per meter Electric Field you provided.</div>
<div> </div>
<div>If you can't stay focused on this topic, i'm out of here.</div>
<div> </div>
<div>Fred</div>
<div> </div>
<div><span class="gmail_quote">On 9/2/07, <b class="gmail_sendername">Frederick Sparber</b> <<a href="mailto:fsparber@gmail.com">fsparber@gmail.com</a>> wrote:</span></div>
<div>
<blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div><br>Nick Reiter wrote:</div>
<div> </div>
<div>" I played a little today with a Zr foil disc I plated<br>with electroless Ni, which in theory should have<br>provided about a 1 volt work function differential,<br>with Ni being negative to the outside. I didn't see
<br>any net attraction to the positive plate over a three<br>foot thread dangle, but the disc did instantly pivot<br>at about 5 kV (over about 15cm distance between<br>plates) to align it's diameter with the e-field. I
<br>can try batteries and nested cylinders as well."</div>
<div> </div>
<div>Borrowing from Metal-Insulator-Metal (MIM) capacitor technology used </div>
<div>in computer chip manufacture, I think a clean aluminum foil, tube,plate, or rod</div>
<div>given a flash anodizing using an ammonium phosphate-glycerin anodizing</div>
<div>bath followed by electroless nickel and nickel (or copper) electroplating will bear fruit.</div>
<div> </div>
<div>This puts the negative (high work function material) on the outside of</div>
<div>the "no net charge contact potential device" where it should repel</div>
<div>the earth's negative charge in the ~ 120 volt per meter "fair weather field"</div>
<div>with a force F = 120 * C * V (Newtons).</div>
<div> </div>
<div>Since Charge Q equals C * V and Capacitance C is a function of MIM )or Metal-Capacitance-Metal</div>
<div>area,optimization of weight and area is required for net lift.</div>
<div> </div>
<div>Fred</div>
<div><br> </div></blockquote></div><br>